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(F)=6F^2-2F-3
We move all terms to the left:
(F)-(6F^2-2F-3)=0
We get rid of parentheses
-6F^2+F+2F+3=0
We add all the numbers together, and all the variables
-6F^2+3F+3=0
a = -6; b = 3; c = +3;
Δ = b2-4ac
Δ = 32-4·(-6)·3
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-9}{2*-6}=\frac{-12}{-12} =1 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+9}{2*-6}=\frac{6}{-12} =-1/2 $
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